An isomer of `C_(5)H_(13) N (A)` on action of `HNO_(2)` gives B The compound B have no reaction with sodium metal . It reacts with `SOCI_(2)` to form C . The compound C on Wurtz synthesis gives 3, 3, 4 ,4- tetramethyl hexane. Which of the following is A ?

Options

A. `C_(2) H_(5) - overset( CH_(3))overset(|) underset(CH_(3))underset(|)( C ) - NH_(2)`
B. `CH_(3) - CH_(2) - overset(NH_(2))overset(|)(C H) - C_(2) H_(5)`
C. `CH_(3) - overset(CH_(3)) overset(|) (C H) - overset(CH_(3))overset(|)( C H) - NH_(2)`
D. `(CH_(3))_(3) C- CH_(2) - NH_(2)`

Answer

A

Explanation

`C_(2) H_(5) - overset( CH_(3))overset(|) underset(CH_(3))underset(| ) (C )- NH_(2) + HNO_(2) to`
`C_(2) H_(5) - overset( CH_(3)) overset(|) underset( CH_(3)) underset(|) (C )- OH + N_(2) + H_(2) O`
`C_(2)H_(5) - overset(CH_(3)) overset(|) underset(CH_(3)) underset(|)( C ) - OH + SOCI_(2) to C_ (2) H_(5) - overset(CH_(3)) overset(|) underset(CH_(3)) underset(|) (C ) - CI + SO_(2) + HCI`
`(C ) `
`C_(2) H_(5) - overset( CH_(3)) overset(|) underset( CH_(3)) underset(|) (C ) - CI + 2N/A + CI - overset( CH_(3)) overset(|) underset(CI) underset(|) (C )- C_(2) H_(5) to`
`C_(2) H_(5)- overset( CH_(3)) overset(|) underset( CH_(3) ) underset(|) (C )- overset(CH_(3)) overset(|) underset(CH_(3)) underset(|) (C )- C_(2) H_(5)`