In a certain reaction, `10%` of the reactant decomposes in one hour, `20%` in two hours, `30%` in theee hours, and so on. The dimenison of the velocity constant (rate constant) are

Options

A. `"hour"^(-1)`
B. `mol litre^(-1) "hour"^(-1)`
C. `litre mol^(-1) sec^(-1)`
D. `mol sec^(-1)`

Explanation

For a zero order reaction, `k = x/t`
i.e. `k= (10 mol L^(-1))/(1 hr)= 10 mol L^(-1)hr^(-1)`
`k=(20mol L^(-1))/(2hr)= 10 mol L^(-1) hr^(-1)`
`k = (30 mol L^(-1))/(3hr)= 10 mol L^(-1) hr^(-1)`
Hence dimensions of the velocity constant are mol `L^(-1) hr^(-1)`