For a chemical reaction `A_2 +2 B to` Products, the rate con trolling step is `A=1/2B to C`. If the cone. of B is tripled, the rate of reaction will

Options

A. remain the same
B. become four times
C. become 1.732 times
D. become double

Explanation

The slow step of the reaction is :
`A + 1/2B to C, " rate low is,"(dx)/(dt)=k[A][B]^(1//2)`
On tripling the concentration of B, the rate will become `(3)^(1//2)= 1.732` times of the original rate.