For a chemical reaction `2X + Y rarrZ`, the rate of appearance of `Z` is `0.05 mol L^(-1) min^(-1)`. The rate of diappearance of `X` will be

Options

A. 0.05 mol `L^(-1)` per hour
B. 0.05 mol `L^(-1)` per min.
C. 0.1 mol `L^(-1) min^(-1)`
D. 0.25 mol `L^(-1)` per min.

Explanation

Rate `= -1/2(d[X])/(dt)=+(d[Z])/(dt)`
`=0.05 mol L^(-1) mi n^(-1)`
`:. -(d[X])/(dt)=2 xx 0.05 = 0.1 mol L^(-1) mi n^(-1)`