The rate of a reaction gets doubled when the temperature changes from `7^(@)C` to `17^(@)C`. By what factor will it change for the temperature change from `17^(@)C` to `27^(@)C` ?

Options

A. 1.81
B. 1.71
C. 1.91
D. 1.76

Explanation

(i) `log. (k_2)/(k_1)=E_a/(2.303R)[(T_2-T_1)/(T_1T_2)]`
`T_1 = 280 K, T_2= 290K, K_2/k_1=2`
From (i) `E_a = 46798J`
(ii) `log. (k_2)/k_1= E_a(2.303R)[(T_2'-T_1')/(T_1'T_2')]`=
`:. T_1'= 290 K, T_2' = 300 K and E_a= 46798 J`
From (ii) `log. (K_2)/(K_1)= 0.28`
`k_2/k_1= Al (0.28)= 1.91`