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In hydrogenation reaction at 25^(@)C, it...

In hydrogenation reaction at `25^(@)C`, it is observed that hydrogen gas pressure falls from 2 atm to 1.2 atm isn 50 min. Calculate the rate of reaction in molarity per sec. (R=0.0821 litre -atm `"degree"^(-1) "mol"^(-1))`

A

`1.09xx 10^(-6)`

B

`1.09 xx 10^(-5)`

C

`1.09 xx 10^(-7)`

D

`1.09xx 10^(-8)`

Text Solution

Verified by Experts

The change in molarity (PV = nRT)
`:. n/V= (DeltaP)/(RT)=0.8/(0.0821xx273)= 0.0327`
`:.` rate of reaction = change in molarity per sec
`:. M/sec=(0.0327)/(50xx 60)= 1.09xx 10^(-5) " mol litre"^(-1)sec^(-1)`
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