A gaseous `A_(2)(g) rarr B(g) +(1)/(2) C(g)`, shows increase in pressure from 100 mm to 120 mm in 5 min. The rate of disappearance of `A_(2)` is

Options

A. 4
B. 8
C. 16
D. 2

Explanation

`A_(2)(g) to B (g) + 1/2 C (g)`
`:. -(d[A_2])/(dt)=2(d[D])/(dt)=(d[B])/(dt)`
Also the increase in pressure is due to the formation of C because one mole of `A_2` gives one mole of B and half mole of C.
Thus,
`-(d[A])/(dt)=2(d[C])/(dt)=2(120-100)/(5)= 8 m m mi n^(-1)`