`99%` at a first order reaction was completed in `32 min`. When will `99.9%` of the reaction complete.

Options

A. 56 min
B. 26 min
C. 19 min
D. 48 min

Explanation

`x_1=99/100=0.99a`
`k = 2.303/32 log. (a)/(a-0.99a)`
`= 2.303/32 log 10^2 =2.303/ 16 mi n^(-1)`
`x_2 = 99.9/100=0.999a`
`t_(99.9%)=2.303/100log. (a)/(a-0.999a)`
`= 2.303/k log 10^3 = (3xx 2.303)/2.303xx 16`
=48 min.