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In the following first order reactions: ...

In the following first order reactions:
`A+ "Reagent" overset(K_(1))(rarr) Product`
`B+ "Reagent" overset(K_(2))(rarr) Product`
The ratio of `K_(1)//K_(2)` when only `50%` of `B` reacts in a given time when `94%` of `A` has been reacted is:

A

4.06

B

0.246

C

2.06

D

0.06

Text Solution

Verified by Experts

For 50% B reacted, `k_2= 2.303/t_2 log. (100)/50`
For 94% A reacted, `k_2= 2.303/t_1 log. (100)/6`
`:.k_2/k_1= 0.3010/1.2218= 0.246 and k_1/k_2= 4.06`
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