Mathematical representation for `t_(1//4)` life i.e., when `1//4th` reaction is over, is given by:

Options

A. `t_(1//4)= 2.303/klog4`
B. `t_(1//4)=2.303/klog2`
C. `t_(1//4)= 2.303/k log.(4)/3`
D. `t_(1//4)= 2.303/k log (3)/4`

Explanation

`k = 2.303/tlog. (a)/((a-x))`
if `t=t_(1//4), x = a//4`
`:.t_(1//4)= 2.303/klog. (a)/((a-a//4)) = 2.303/k log. (4)/3`