The rate constatnt of a second order reaction is ` 10^(-2) "mol"^(-1)` litre `sec^(-1)`. The rate constant when expressedd in ` cm^(3)" molecule"^(-1) "min"^(-1)` is :

Options

A. `9.96 xx 10^(-22)`
B. `9.96 xx 10^(-23)`
C. `9.96 xx 10^(-21)`
D. `1.004 xx 10^(-24)`

Explanation

`k = 10^2 mol^(-1)litre sec^(-1)`
`=(10^2xx 1000xx 60)/(6.02 xx 10^23) c c "molecule"^(-1)mi n^(-1)`
`=9.9618 xx 10^(-22) c c" molecule"^(-1) mi n^(-1) `