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The activation energy of a reaction is 9...

The activation energy of a reaction is 9 kcal/mol. The increase in the rate constant when its temperature is raised from 395 to 300K is approximately

A

0.1

B

0.5

C

1

D

0.25

Text Solution

Verified by Experts

`log. (k_2)/(k_1)= 9000/ (2.303xx 2)(5/(395 xx 300))= 0.1103`
Hence, `k_2/k_1 = 1.288`
or `k_2 = 1.288 k_1, i.e., ` increase = 38.8 %`~~`25%
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