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Values of dissociation constant, K(a) a...

Values of dissociation constant, ` K_(a)` are given as follows :
Acid `K_(a)`
`HCN 6.2xx10^(-10)`
`HF " " 6.6xx10^(-4)`
`HNO_(2) " " 7.2xx10^(-4)`
Correct order of increasing base strength of the base `CN^(-), F^(-) and NO_(2)^(-)` will be :

A

`F^(-) lt CN^(-) lt NO_(2)^(-)`

B

`NO_(2)^(-) lt CN^(-) lt F^(-)`

C

`F^(-) lt NO_(2)^(-) lt CN^(-)`

D

`NO_(2)^(-) lt F^(-) lt CN^(-)`

Text Solution

Verified by Experts

The correct Answer is:
C

Higher the value of `K_(a)` lower will be the value of `pK_(a)` ie., higher will be the acidic nature. Further since `CN^(-),F^(-) and NO_(2)^(-)` are conjugate base of the acids HCN, HF and `HNO_(2)` respectively hence the correct order of base strength will be
`F^(-) lt NO_(2)^(-) lt CN^(-)`
`(because` stronger the acid weaker will be its conjugate base)
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