For the following three reaction a, b and c, equilibrium constants are given :
(i) `CO(g) * H_(2)O_(g) hArr CO_(2)(g) * H_(2)(g), K_(1)`
(ii) `CH_(4)(g) * H_(2)O(g) hArr CO(g) * 3H_(2)(g), K_(2)`
`(iii) CH_(4)(g)+2H_(2)O(g) hArr CO_(2)(g)+4H_(2)(g), K_(3)`

Options

A. `K_(1)sqrt(K_(2))=K_(3)`
B. `K_(2)K_(3)=K_(1)`
C. `K_(3)=K_(1)K_(2)`
D. `K_(3).K_(2)^(3)=K_(1)^(2)`

Answer

C

Explanation

Reaction (c) can be obtained by adding reactions (a) and (b) therefore `K_(3)=K_(1)K_(2)`
Hence (c ) is the correct answer.