An organic compound contains `C=40% , H=13.33% and N=46.67%`. Its empirical formula would be

Options

A. `CHN`
B. `C_(2)H_(2)N`
C. `CH_(3)N`
D. `C_(3)H_(2)N`

Answer

C

Explanation

As in above question, `C=(40)/(12)=3.33: H=(13.33)/(1)=13.33: N=(46.67)/(14)=3.34`
Relative No. of atoms `C=(3.33)/(3.33)=1, H=(13.33)/(3.33)=4, N=(3.34)/(3.33)=1`
`therefore` Empirical formula`=CH_(4)N`