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The electrode potential E ((zn^(2)+//ze)...

The electrode potential `E _((zn^(2)+//ze))` of a zinc electrode at `25^(@)C` with an aqueous solution of `0.1 M ZnSO_(4)` is `[E_((Zn^(2+)//Zn))^(@) =-0.73V."Assume"(2.30.0RT)/(F)=0.06at 298K].`

A

`+0.73`

B

`-0.79`

C

`0.82`

D

`-0.70`

Text Solution

Verified by Experts

The correct Answer is:
B
F or `Zn^(2+) to Zn`
`E_(Zn^(2+)//Zn)= E_(Zn^(2+)//Zn)-(2.303RT)/(nF) log ""([Zn])/([Zn^(2+)])`
`=-0.76 -(0.06)/(2) log ""(1)/([0.1])=-0.76-0.03`
`E_(Zn^(2+)//Zn)=-0.79V`
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