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For a spontaneous reaction theDeltaG) eq...

For a spontaneous reaction the`DeltaG)` equilibrium constnat `(K)and E_("Cell")^(@)` eill be respectively

A

`-ve gt 1, -ve`

B

`-ve, lt 1, -ve`

C

`+ve, gt 1, -ve`

D

`-ve, 1, +ve`

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The correct Answer is:
D
For spontaneous reaction `DelgaG` should be negative. Equilibrium constant should be more than one
`(DeltaG =-2.303 RT log K_(e), If K _(c)=1` then `DeltaG=0, If K_(c)lt 1`
then `DeltaG =+ ve).` Again `Delta G=-nFE_(cell)^(@)`
`E _(cell)^(@)` must be + ve have `Delta G-vc.`
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