Conductanceof `0.1 MKCl` (condiuctivity = X `ohm^(-1)cm^(-1))` filled in a condictivity cell is Y `ohm^(-1).` If the conductance of 0.1 Mno OH filled in the csamecell is Z `ohm^(-1),` them olar conductance of NaOH will be

Options

A. `10^(3) (XZ)/(Y)`
B. `10^(4)(XZ)/(Y)`
C. `10(XZ)/(Y)`
D. `0.1 (XZ)/(Y)`

Answer

B

Explanation

Conductivity (X) = conductance (c ) `xx` cell constnat
`therefore` Cell constant `=X/Y`
Conductivity of `NaOH = X/Y.Z`
`Delta M (NaOH) = X/Y . Z xx (1000)/(0.1) =(XZ)/(Y) 10^(4)`