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The resistance of 0.1 N solution of a sa...

The resistance of 0.1 N solution of a salt is found to be `2.5xx 10^(3)ohm.` The equivalent conductance of the solution is (cell constnat `=1.15 cm^(-1))`

A

`4.6`

B

`5.6`

C

`6.6`

D

`7.6`

Text Solution

Verified by Experts

The correct Answer is:
A
Specific conductance = Conductance `xx` Cell constant
`k =(1)/(2.5xx 10^(3)) xx1.15,`
`^^_(cq) =(1.15)/(2.5xx10^(3)) xx(100)/(0.1) =4.6`
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