When electric current is passed through acidified water, 1 12 mL of hydrogen gas at STP collected at the cathode in 965 seconds. The current passed in amperes is

Options

A. `1.0`
B. `0.5`
C. `0.1`
D. `2.0`

Answer

A

Explanation

112 mL of `H_(2)` at `STP =(2xx 112g)/(22400)`
(Since 22400 mL at STP =M.wt)
Amount deposiled `=(Eq. wt xxi xxt)/(96500)`
`therefore (2xx 112)/(22400) =(1xx965xxi)/(96500)`
`i=1` amp