Which of the following shows nitrogen with its increasing order of oxidation number ?

Options

A. `NO lt N_(2)O lt NO_(2) lt NO_(3)^(-) lt NH_(4)^(+)`
B. `NH_(4)^(+) lt N_(2)O lt NO_(2) lt NO_(3)^(-) lt NO`
C. `NH_(4)^(+) lt N_(2)O lt NO lt NO_(2) lt NO_(3)^(-)`
D. `NH_(4)^(+) lt NO lt N_(2)O lt NO_(2) lt NO_(3)^(-)`

Answer

C

Explanation

`{:("Compound","O.S. of N"),(N_(2)O," "+1),(NO," "+2),(NO_(2)," "+4),(NO_(3)^(-)," "+5),(NH_(4)^(+)," "-3):}`
Therefore increasing order of oxidation state of N is :
`NH_(4)^(+) lt N_(2)O lt NO lt NO_(2) lt NO_(3)^(-)`