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The "spin-only" magnetic moment [in unit...

The "spin-only" magnetic moment [in units of Bohr magneton, `(mu_(B))`] of `Ni^(2+)` in aqueous solution would be (At. NO. Ni=28)

A

6

B

1.73

C

2.84

D

4.9

Text Solution

Verified by Experts

The correct Answer is:
C
The number of unpaired electrons in `Ni^(2+)(aq)=2` Water is weak ligand hence no pairing will take place spin magnetic moment
`=sqrt(n(n+2))=sqrt(2(2+2))=sqrt(8)=2.82`
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