Number of moles of `K_(2)Cr_(2)O_(7)` reduced by one mole of `Sn^(2+)` ions is

Options

A. `1/3`
B. 3
C. `1/6`
D. 6

Answer

A

Explanation

`Cr_(2)O_(7)^(2-)+6e^(-)+14H^(+) to 2Cr^(3+)+7H_(2)O`
`Sn^(2+) to Sn^(4+)+2e^(-)`
One mole of `Sn^(2+)` provide 2 mole of `e^(-)` which will reduce `1//3Cr_(2)O_(7)^(2-)`