The copounds which is not coloured is

Options

A. `K_(4)Fe(CN)_(6)`
B. `K_(3)Fe(CN)_(6)`
C. `Na_(2)CdCl_(4)`
D. `Na_(2)CuCl_(4)`

Answer

C

Explanation

In `Na_(2)Cd Cl_(4)`, Cd has oxidatin state +2.
So, its electronic configuration is `4d^(10)4s^(0)`
All the 4d orbitals are fully filled.
hence, there will not be d-d transition resulting in colour. So, it is colourless.