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Calculate the value of log K(3) when log...

Calculate the value of log `K_(3)` when log values of `K_(2),K_(1),K_(4) and K_(4)` respectively are 2.0, 3.20, 4.0 and 11.9 ?

A

`2.0`

B

2.7

C

3

D

2.5

Text Solution

Verified by Experts

The correct Answer is:
B
`beta=K_(1)K_(2)K_(3)K_(4)`
long `beta=log(K_(1)K_(2)K_(3)K_(4))`
`logbeta=logK_(1)+logK_(2)+logK_(3)+logK_(4)`
`logK_(3)=11.9-(3.20+2.0+4.0)`
`logK_(3)=2.7`
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