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Arrange the following compounds in order...

Arrange the following compounds in order of increasing dipole moment .
Toluene `(I)` m-dichlorobenzene `(II)`
o-dichlorobenzene `(III)` . P-dichlorobenzene `(IV)` .

A

`IltIVltIIltIII`

B

`IVltIlrIIltIII`

C

`IVltIltIIIltII`

D

`IVltIIltIltIII`

Text Solution

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The correct Answer is:
B
n p-dichlorobenzene, the two equal dipoles are in opposite direction, hence the molecule has zero dipole moment. In o-and m-dichlorobenzenes, the two dipoles are at `60^(@) and 120^(@)` apart respectively, and thus according to parallelogram law of forces, the dipole moment of o-dichlorobenzene is much higher than that of m-isomer. Lastly, toluene with a +I group possesses I ittle dipole moment. Thus the overall order is
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