A 40 kg slab rests on a frictionless floor . A 10 kg block rests on top of the slab (Fig . 7. 121). The static coefficient of friction between the block and the slab is `0.60` while the kinetic coefficient is `0.40` . The 10 kg block is acted upon by a horizontal force of 100 N . if g = `9.8 m//s^(2)` the resulting acceleration of the slab will be :

A 40kg slab rests on a frictionless floor as shown in the figure. A 10kg block rests on the top of the slab. The static coefficient of friction between the block and slab is 0.60 while the kinetic friction is 0.04 . The 10kg block is acted upon by a horizontal force 100N. if g=9.8m//s^(2) , the resulting acceleration of the slab will be.

A 40 kg slb rest on a frictionless floor as shown in the figure. A 10 kg block rests on the top of the slab. The static corfficient of friction between the block and slab is 0.60 while the kinetic friction is 0.40 the 10 kg block is acted upon by a horizontal force 100N. If g=9.8(m)/(s^2) , the resulting acceleration of the slab will be.

A 42 kg slab rests on a frictionless floor A 9.7 kg block rests on the top of the slab as shown in the figure. The co-efficient of static friction between the block and the slab is 0.53, while the co-efficient of kinetic friction is 0.38. The 9.7 kg block is acted upon by a horizontal force of 110 N. What are the resulting accelerations of (a) the block, and (b) the slab? (Take g=9.8m//s^(2) )

A 40 kg slab rests on a frictionless floor. A 10 kg block rests on top of the slab. The coefficient of friction between the block and the slab is 0.40. The 10 kg block is acted upon by a horizontal force of 100 N. If g=10m//s^(2) , the resulting acceleration of the slab will be

A 40 kg slab rests on a frictionless floor. A 10 kg block rests on top of the slab. The coefficient of friction between the block and the slab is 0.40. The 10 kg block is acted upon by a horizontal force of 100 N. If g=10m//s^(2) , the resulting acceleration of the slab will be

A 40kg slab rests on a frictionless floor. A 10kg block rests on top of the slab. the static coefficient of friction between the block and the slab is 0.60 and The coefficient kinetic friction between the block and the slab is 0.40. A horizontal force of 100N is applied on the 10kg block. Find the resulting acceleration of the slab. (g=10ms^(-1))

A 40 kg slab rests on a frictionless floor . A 10 kg block rests on the top of the slab . [Fig. 7.81 (a)] . The coefficients of static and dynamic friction are 0.60 and 0.40 respectively . The 10 kg block is pulled by a horizontal force of 100 N . what are the resulting accelerations of (a) the block (b) the slab ? ( g = 10 m// s^(2) )

Block A of mass 5 kg is resting on a frictionless floor. Another block B of mass 7kg is resting on it as shown in the figure. The coefficient of friction between the blocks is 0.5 while kinetic friction is 0.4. If a force of 100 N is applied to block B, the acceleration of the block A will be ( g =10 ms^(-2)) :