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A straight highway leads to the foot of a tower of height 50 m. From the top of tower, the angles of depression of two cars standing on the highway are `30^@` and `60^@` respectively. What is the distance between the two cars and how far is each car from the tower?

Text Solution

Verified by Experts

In`/_ABC` `tan60=(AB)/(BC)=50/x=sqrt3` So, `x=50/sqrt3m`
In `/_ABD` `tan30=(AB)/(BD)=50/(x+y)=1/sqrt3` `50sqrt3=x+y`
Hence, `y=100/sqrt3m`
Distance between cars `y=100/sqrt3m`
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