Consider the following equation
`Ca(OH)_(2)+H_(3)PO_(4) rarr CaHPO_(4)+2H_(2)O`
The equivalent mass of phosphoric acid `(H_(3)PO_(4))` is

In the reaction CA(OH)_(2)+H_(3)PO_(4) rarr Ca_(3)(PO_(4))_(2)+H_(2)O , the equivalent mass of H_(2) O is: (M molecular mass)

In the reaction, H_3PO_4+Ca(OH)_2rarrCaHPO_4+2H_2O, the equivalent mass of H_3PO_4 is

In the reaction, H_3PO_4+Ca(OH)_2rarrCaHPO_4+2H_2O, the equivalent mass of H_3PO_4 is

In the reaction \(2NaOH+H_{3}PO_{4}\rightarrow Na_{2}HPO_{4}+2H_{2}O\) ,the equivalent weight of phosphoric acid \(H_{3}PO_{4}\) is

STATEMENT-1 : In the given reaction, NaOH+H_(3)PO_(4)rarr NaH_(2)PO_(4)+H_(2)O equivalent mass of H_(3)PO_(4) is M//3 STATEMENT-2 : H_(3)PO_(4) is tribasic acid.

STATEMENT-1 : In the given reaction, NaOH+H_(3)PO_(4)rarr NaH_(2)PO_(4)+H_(2)O equivalent mass of H_(3)PO_(4) is M//3 STATEMENT-2 : H_(3)PO_(4) is tribasic acid.

STATEMENT-1 : In the given reaction, NaOH+H_(3)PO_(4)rarr NaH_(2)PO_(4)+H_(2)O equivalent mass of H_(3)PO_(4) is M//3 STATEMENT-2 : H_(3)PO_(4) is tribasic acid.