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Determine the point where the line 2y+x=3 , is normal to the curve y=x^(2) .

The point where normal to y=x^(2)-2x+3 is parallel to Y-axis is ……….

The point on the intersection of the tangents drawn to the curve x^2y=1-y at the points where it is intersected by the curve x^2y=1-y at the points where it I intersected by the curve xy=1-y is

If (x-1)^2+(y-2)^2=0 , where x and y are integers, then the value of 2x+3y is :

The equation of tangent at those points where the curve y=x^2-3x+2 meets x-axis are:

If (x-1)^2+(y-2)^2 = (x-1)(y-2) , where x and y are integers, then the value of 2x + 3y is

The points on the curve x^2=3-2y , where the tangent is parallel to x+y=2, is

If x ^(2) + y^(2) - 14 x - 6y - 6=0, then the maximum possible value of 3x + 4y is (where (x,y) is a point on the given curve)