[" 3.58"],[" (14) "(x)/(a)=(y)/(b)],[" ax "+by=a^(2)+b^(2)]

(x)/(a)-(y)/(b)=0,ax+by=a^(2)+b^(2)

Solve: (x)/(a)+(y)/(b)=2,quad ax-by=a^(2)-b^(2)

x+y=a+b,ax-by=a^(2)-b^(2)

Solve for xandy: (x)/(a)+(y)/(b)=2,ax-by=a^(2)-b^(2)

The value of y which satisfies (x)/(a)=(y)/(b) and ax+by=a^(2)+b^(2) is

{:(x + y = a + b),(ax - by = a^(2) - b^(2)):}

y = (ax + b) e^(-2x)

If a circle passes through the point (a, b) and cuts the circle x^2 + y^2 = 4 orthogonally, then the locus of its centre is (a) 2ax+2by-(a^(2)+b^(2)+4)=0 (b) 2ax+2by-(a^(2)-b^(2)+k^(2))=0 (c) x^(2)+y^(2)-3ax-4by+(a^(2)+b^(2)-k^(2))=0 (d) x^(2)+y^(2)-2ax-3by+(a^(2)-b^(2)-k^(2))=0

If (x^(2))/(by+cz) = (y^(2))/(ax+ cz) = (z^(2))/(ax + by)=2 (a)/(x+2a) + (b)/(y+2b) + (c )/(z+2c) = ?