Home
Class 9
MATHS
In the given figure, AB =4 cm and BD=4sq...

In the given figure,` AB =4 cm and BD=4sqrt3 cm`. Then the relation between `Delta[area of triangle ADC] and S`(shaded area bounded by three semicircles) is:

Promotional Banner

Similar Questions

Explore conceptually related problems

In the figure, AB=12 cm AD=4 cm. Then a) BD=---- cm. b) The ratio of the areas of triangle ADC and triangle BDC is =…….

In the given figure,AB=4cm,BC=3cm, the area of shaded portion is:

In the given figure, AC= 6 cm, AB= 5 cm and /_BAC=30^(@) . Find the area of the triangle.

In the given figure, /_B = /_E, /_ACD = /_BCE, AB = 10.4 cm and DE = 7.8 cm . Find the ratio between areas of the Delta ABC and Delta DEC .

If the sides of a triangle are 3 cm, 4 cm and 5 cm, then the area is

If the sides of a triangle are 5 cm, 4 cm and sqrt(41) cm, then the area of the triangle is

In the adjoining figure, BD = DC and AE = ED. Prove that area of Delta ACE = (1)/(4) " area of " Delta ABC