The path of particle is shown in figure. The ratio of distance travelled and magnitude of displacement is :

EF=AB=2m
FG =BC =2m
CD=DE =1m

A particle moves from A to B in a circular path of radius R covering an angle theta as shown in figure. Find the ratio of magnitude of distance and magnitude of displacement of the particle.

A particle moved 5 m towards east then moved 8 m towards west. What is the total distance travelled and the magnitude of displacement?

A particle travels from A to B path shown in figure, then the displacement of particle is : .

A particle travels from A to B path shown in figure, then the displacement of particle is : .

A particle moved 5 m towards east and then moved 8 m towards west. What is the total distance travelled and the magnitude of displacement?

The velocity of a particle varies with time as per the figure shown. The distance travelled by the particle in 10 seconds is ?(m/s)

A particle moves along a path ABCD as shown in the figure. Then the magnitude of net displacement of the particle from position A to D is:

A particle moves along a path ABCD as shown in the figure. Then the magnitude of net displacement of the particle from position A to D is:

A person walks along the path shown in Fig. 3.53. The path from B to C is semicircular and centred at O. If the magnitude of displacment of the person is 2m, distance travelled by him is nearly :