A sample of 100 g water is slowly heated from `27^@C` to `87^@C`. Calculate the change in the entropy of the water specific heat capacity of water `=4200(J)/(kg-K)`

Explanation

`DeltaQ=msDeltaT`
`DeltaS=(DeltaQ)/(T)=(msDeltaT)/(T)`
The total change in entropy as temperature from `T_1` to `T_2`r
`S_1-S_2=int_(T1)^(T2)ms(dT)/(T)`
`=msln((T_2)/(T_1))`
`=0.1xx4200ln((87+273)/(27+273))`
`=420ln(1.2)(J)/(K)`