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(i) DeltaW(AB)=5P0V0 (ii) DeltaW(BC)=0...


(i) `DeltaW_(AB)=5P_0V_0`
(ii) `DeltaW_(BC)=0`
(iii) `DeltaW_(CA)=-2P_0V_0`
(iv) `DeltaW_(ABCA)=3P_0V_0`

A

(i),(iii)

B

(ii),(iii)

C

(iii),(iv)

D

all

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaW_(AB)=(1)/(2)(P_0+4P_0)(3V_0-V_0)=5P_0V_0`
`DeltaW_(BC)=0`
`DeltaW_(CA)=-P_0(3V_0-V_0)=-2P_0V_0`
`DeltaW_(ABCA)=DeltaW_(AB)+DeltaW(BC)+DeltaW_(CA)=3P_0V_0`
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