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In a given process on an ideal gas, dW=0...

In a given process on an ideal gas, `dW=0 and dQlt0.` Then for the gas

A

the temperature will decrease

B

the volume will increase

C

the pressure will remain constant

D

the temperature will increase

Text Solution

Verified by Experts

The correct Answer is:
A
`dQ=dU+dW`
`dW=0impliesdQ=dU=nC_Vdt`
`dQlt0` i.e., `nC_VdTlt0` i.e., temperature falls
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