An ideal gas is initially at temperature T and volume V. Its volume is increased by `DeltaV` due to an increase in temperature `DeltaT,` pressure remaining constant. The quantity `delta=(DeltaV)/(VDeltaT)` varies with temperature as

Options

A.
B.
C.
D.

Answer

C

Explanation

`(V)/(T)=(nR)/(P)=`constant
`(V)/(T)=(V+DeltaV)/(T+DeltaT)`
`VT+VDeltaT=VT+DeltaVT`
`VDeltaT=DeltaVT`
`(DeltaV)/(VDeltaT)=(1)/(T)`
`delta=(1)/(T)`
`delta` v/s T will be rectangular hyperbola