A cylindrical tube of uniform cross-sect...

A cylindrical tube of uniform cross-sectional area A is fitted with two air tight frictionless pistons. The pistons are connected to each other by a metallic wire. Initially the pressure of the gas is `P_0` and temperature is `T_0`, atmospheric pressure is also `P_0`. Now the temperature of the gas is increased to `2T_0`, the tension in the wire will be

`2P_0A`

`P_0A`

`(P_0A)/(2)`

`4P_0A`

Text Solution

Verified by Experts

The correct Answer is:

`n=(P_0V)/(RT_0)=(P')/(R.2T_0)impliesP'=2P_0`
`P_0A+T=2P_0A`
`T=P_0A`

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