The average degrees of freedom per molecule for a gas are 6. The gas performs `25 J` of work when it expands at constant pressure. The heat absorbed by gas is

Options

A. 75 J
B. 100 J
C. 150 J
D. 125 J

Answer

B

Explanation

`f=6`
`gamma=1+(2)/(f)=1+(2)/(6)=(4)/(3)`
`C_P=(gammaR)/(gamma-1)=((4)/(3)R)/((4)/(3)-1)=4R`
`DeltaW=nRDeltaT`
`(DeltaQ)_P=nC_PDeltaT`
`(DeltaW)/((DeltaQ)_(P))=(R)/(C_P)=(R)/(4R)=(1)/(4)`
`(DeltaQ)_P=4DeltaW=4xx25=100J`