A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to
`v(x) = beta x^(-2 n)`
where `beta` and `n` are constant and `x` is the position of the particle. The acceleration of the particle as a function of `x` is given by.

Options

A. `- 2 nb^(2) x^(-4n -1)`
B. `- 2 nb^(2) x^(-2n +1)`
C. `- 2 nb^(2) x^(-4n + 1)`
D. `- 2 nb^(2) x^(-2n - 1)`

Explanation

`v = bx^(-2xn)`
`(dv)/(dx) = (b) (-2n) x^(-2n - 1)`
`a = v (dv)/(dx) = bx^(-2n) (b) (-2n) x^(-2n - 1)`
`= - 2nb^(2) x^(-4n - 1)`