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A ship A is moving Westwards with a spee...

A ship A is moving Westwards with a speed of `10kmh^(-1)` and a ship B 100km South of A is moving northwards with a speed of `10kmh^(-1)`. The time after which the distance between them shortest is

A

`5 h`

B

`5 sqrt(2) h`

C

`10 sqrt(2) h`

D

`0 h`

Text Solution

Verified by Experts

`v_(B//A) = vecv_(B)-vecv_(A)=vecv_(B)+(-vecv_(A))`
`AB'`: Shortest distance
`t = (BB')/(v_(B//A)) = (100 cos 40^(@))/(10 sqrt2)`
`=5 h`

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