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A rod of weight w is supported by two pa...

A rod of weight `w` is supported by two parallel knife edges `A` and `B` and is in equilibrium in a horizontal position. The knives are at a distance `d` from each other. The centre of mass of the rod is at a distance `x` from `A`.

A

`(Wd)/(x)`

B

`(W(d - x))/(x)`

C

`(W(d - x))/(d)`

D

`(W x)/(d)`

Text Solution

Verified by Experts

Taking torque about `B`
`N_(A) d = W (d - x) implies N_(A) = (W (d -x))/(d)`
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