A paritcal of mass `10 g` moves along a circle of radius `6.4 cm` with a constant tangennitial acceleration. What is the magnitude of this acceleration . What is the magnitude of this acceleration if the kinetic energy of the partical becomes equal to `8 xx 10^(-4) J` by the end of the second revolution after the beginning of the motion?

Options

A. `0.2 m//s^(2)`
B. `0.1 m//s^(2)`
C. `0.15 m//s^(2)`
D. `0.18 m//s^(2)`

Explanation

`K = (1)/(2) mv^(2) implies 8 xx 10^(-4) = (1)/(2) xx 10 xx 10^(-3) v^(2)`
`implies v^(2) = 0.16`
`v^(2) = u^(2) + 2 a_(t) (2 xx 2 piR)`
`0.16 = 2 a_(1) (4pi xx 6.4 pi 10^(-2))`
`a_(t) = (10)/(32 pi) = 0.1 m//s^(2)`