A refrigerator works between `4^(@)C` and `30^(@)C`. It is required to remove `600 calories` of heat every second in order to keep the temperature of the refrigerator space constant.The power required is (Take `1calorie= 4.2 J`)

Options

A. `2.365 W`
B. `23.65 W`
C. `236.5 W`
D. `2364 W`

Explanation

`T_(2) = 4^(@)C = 277 K, T_(1) = 30^(@)C = 303 K`
`Q_(2) = 600 cal`
`(Q_(1))/(Q_(2)) = (T_(1))/(T_(2)) implies (Q_(2) + W)/(Q_(2)) = (T_(1))/(T_(2))`
`W = 236.5 W`