A black body is at a temperature of `5760 K`. The energy of radiation emitted by the body at wavelength `250 nm` is `U_(1)` at wavelength `500 nm` is `U_(2)` and that at `1000 nm` is `U_(3)`. Wien's consant, `b = 2.88 xx 10^(6) nmK`. Which of the following is correct?

Options

A. `U_(1) = 0`
B. `U_(3) = 0`
C. `U_(1) gt U_(2)`
D. `U_(2) gt U_(1)`

Explanation

`T_(1) = 5760 K, lambda_(m) T = 2.88 xx 10^(6)`
`lambda_(m) = (2.88 xx 10^(6))/(5760) = 500 nm`
`U_(2) gt U_(1)`