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A block of mass `m` is placed on a smooth inclined wedge ABC of inclination theta as shown in the figure. The wedge is given an acceleration `a` towards the right. The relation between a and theta for the block to remain stationary on the wedge is.

A

`a = g cos theta`

B

`a = g tan theta`

C

`a = (g)/(sin theta)`

D

`a = (g)/(cosec theta)`

Text Solution

Verified by Experts

The correct Answer is:
B

Block will remain stationary of wedge if
`ma cos theta = mg sin theta`
`:. a = g tan theta`
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