A pendulum is hung the roof of a sufficiently high huilding and is moving freely to and fro like a simple harmonic oscillator .The acceleration of the bob of the pendulum is `20m//s^(2)` at a distance of `5m` from the meanposition .The time period of oscillation is

Options

A. `2 s`
B. `1 s`
C. `pi s`
D. `2 pi s`

Answer

C

Explanation

For `SHM, a = - omega^(2) x`
`omega = sqrt((a)/(x)) = sqrt((20)/(5)) = 2`
`:. (2 pi)/(T)` = 2 implies T pi s`