The junction of a `Ni-Cu` thermocouple is maintained to `0^(@)C` and `100^(@)C`. Find the thermo-emf produced. Also, find nautral temperature and inversion temperature. Given `a_(Ni, Cu) = 16.3xx10^(-6)V//.^(@)C, b_(Ni,Cu) = -0.042xx10^(-6)V//(@C)^(2)`.

Explanation

Thermo-emf
`E_(Ni,Cu) = a_(Ni,Cu) T +1/2 b_(Ni,Cu)T^(2)`
`=(16.3xx10^(-6))(100)+1/2(-0.0042xx10^(-6))(100)^(2)`
`=1.42 XX 10^(-3)v`
`t_(N) = -A/B = -(16.3XX10^(-6))/(-0.042xx10^(-6)) = 388^(@)c`
`t_(i) = -2a/b = 776^(@)C`.