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Three equal resistor connected in serie...

Three equal resistor connected in series across a source of enf together dissipate `10 Watt`. If the same resistors aer connected in parallel across the same emf, then the power dissipated will be

A

10 Watt

B

30Watt

C

`10//3 Watt`

D

`90Watt`

Text Solution

Verified by Experts

The correct Answer is:
D

`P_(1) = 10 = (V^2)/(3R) , P_(2) = (V^2)/(R//3)`
`(P_2)/(P_1) = 9 implies P_(2) = 9P_(1) = 90 W`.
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