Two electric bulbs `A` and `B` are designed for the same voltage. Their power ratings are `P_(A)` and `P_(B)` respectively with `P_(A) gt P_(B)` . If they are joined in series across `V` voltage supply

Options

A. `A` will draw more power than `B`
B. `B` will draw more power than `A`
C. the ratio of powers drawn by then will depend on `V`
D. `A` and `B` will draw the same power

Answer

B

Explanation

`R = (V^2)/(P)` , As `R prop 1//P. R_(A) lt R_(B)`

`P_(A) = i^(2)R_(A), P_(B) = i^(2)R_(B)`
`P_(B) gt P_(A)`.